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(8x-12)=(5x+18)
We move all terms to the left:
(8x-12)-((5x+18))=0
We get rid of parentheses
8x-((5x+18))-12=0
We calculate terms in parentheses: -((5x+18)), so:We get rid of parentheses
(5x+18)
We get rid of parentheses
5x+18
Back to the equation:
-(5x+18)
8x-5x-18-12=0
We add all the numbers together, and all the variables
3x-30=0
We move all terms containing x to the left, all other terms to the right
3x=30
x=30/3
x=10
| g+24=30 | | 0.05(7t+6)=0.35(T-5)+2.05 | | -5x+9+24=x | | (89-6x)=(3x+62) | | 293x+3)=3(2x+2 | | 0.15(y-0.2)=20.5-(1-y) | | x+0.75=2x+0.25 | | 0=-0.005x^2+0.25x | | (5x-3)=(147-x) | | 0.05(7t+6)=0.35(T-5)+2.5 | | 85;x-41=44 |