(8x-18)+(7-31)=(13x-9)+(19x-6)

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Solution for (8x-18)+(7-31)=(13x-9)+(19x-6) equation: 



(8x-18)+(7-31)=(13x-9)+(19x-6)

We move all terms to the left:

(8x-18)+(7-31)-((13x-9)+(19x-6))=0

We add all the numbers together, and all the variables

(8x-18)-((13x-9)+(19x-6))+(-24)=0

We add all the numbers together, and all the variables

(8x-18)-((13x-9)+(19x-6))-24=0

We get rid of parentheses

8x-((13x-9)+(19x-6))-18-24=0



We calculate terms in parentheses: -((13x-9)+(19x-6)), so:

(13x-9)+(19x-6)

We get rid of parentheses

13x+19x-9-6

We add all the numbers together, and all the variables

32x-15

Back to the equation:

-(32x-15)



We add all the numbers together, and all the variables

8x-(32x-15)-42=0

We get rid of parentheses

8x-32x+15-42=0

We add all the numbers together, and all the variables

-24x-27=0

We move all terms containing x to the left, all other terms to the right

-24x=27

x=27/-24

x=-1+1/8

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