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(8x-2)(7x)=180
We move all terms to the left:
(8x-2)(7x)-(180)=0
We multiply parentheses
56x^2-14x-180=0
a = 56; b = -14; c = -180;
Δ = b2-4ac
Δ = -142-4·56·(-180)
Δ = 40516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40516}=\sqrt{4*10129}=\sqrt{4}*\sqrt{10129}=2\sqrt{10129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{10129}}{2*56}=\frac{14-2\sqrt{10129}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{10129}}{2*56}=\frac{14+2\sqrt{10129}}{112} $
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