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(8x-2)(7x-5)-(4x-3)(5x-4)=(9x-3)(4x-2)-1
We move all terms to the left:
(8x-2)(7x-5)-(4x-3)(5x-4)-((9x-3)(4x-2)-1)=0
We multiply parentheses ..
(+56x^2-40x-14x+10)-(4x-3)(5x-4)-((9x-3)(4x-2)-1)=0
We calculate terms in parentheses: -((9x-3)(4x-2)-1), so:We get rid of parentheses
(9x-3)(4x-2)-1
We multiply parentheses ..
(+36x^2-18x-12x+6)-1
We get rid of parentheses
36x^2-18x-12x+6-1
We add all the numbers together, and all the variables
36x^2-30x+5
Back to the equation:
-(36x^2-30x+5)
56x^2-36x^2-40x-14x-(4x-3)(5x-4)+30x+10-5=0
We multiply parentheses ..
56x^2-36x^2-(+20x^2-16x-15x+12)-40x-14x+30x+10-5=0
We add all the numbers together, and all the variables
20x^2-(+20x^2-16x-15x+12)-24x+5=0
We get rid of parentheses
20x^2-20x^2+16x+15x-24x-12+5=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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