(8x-2)/3=(12x+8)/6

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Solution for (8x-2)/3=(12x+8)/6 equation: 



(8x-2)/3=(12x+8)/6

We move all terms to the left:

(8x-2)/3-((12x+8)/6)=0

We calculate fractions


8x/()+(-((12x+8)*3)/()=0



We calculate terms in parentheses: +(-((12x+8)*3)/(), so:

-((12x+8)*3)/(

We multiply all the terms by the denominator


-((12x+8)*3)



We calculate terms in parentheses: -((12x+8)*3), so:

(12x+8)*3

We multiply parentheses

36x+24

Back to the equation:

-(36x+24)



We get rid of parentheses

-36x-24

Back to the equation:

+(-36x-24)



We get rid of parentheses

8x/()-36x-24=0

We multiply all the terms by the denominator


8x-36x*()-24*()=0

We add all the numbers together, and all the variables

8x-36x*()=0

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