(8x-2)/7=(x/2)+(3x-2)/4

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Solution for (8x-2)/7=(x/2)+(3x-2)/4 equation: 


x in (-oo:+oo)

(8*x-2)/7 = (3*x-2)/4+x/2 // - (3*x-2)/4+x/2

(8*x-2)/7-((3*x-2)/4)-(x/2) = 0

(8*x-2)/7+(-1*(3*x-2))/4-x/2 = 0

(2*4*(8*x-2))/(2*4*7)+(-1*2*7*(3*x-2))/(2*4*7)+(4*7*(-x))/(2*4*7) = 0

2*4*(8*x-2)-1*2*7*(3*x-2)+4*7*(-x) = 0

22*x-28*x+12 = 0

12-6*x = 0

(12-6*x)/(2*4*7) = 0

(12-6*x)/(2*4*7) = 0 // * 2*4*7

12-6*x = 0

12-6*x = 0 // - 12

-6*x = -12 // : -6

x = -12/(-6)

x = 2

x = 2

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