(8x-20)(8x+8)=180

Solution for (8x-20)(8x+8)=180 equation:

(8x-20)(8x+8)=180

We move all terms to the left:

(8x-20)(8x+8)-(180)=0

We multiply parentheses ..

(+64x^2+64x-160x-160)-180=0

We get rid of parentheses

64x^2+64x-160x-160-180=0

We add all the numbers together, and all the variables

64x^2-96x-340=0

a = 64; b = -96; c = -340;
Δ = b2-4ac
Δ = -962-4·64·(-340)
Δ = 96256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96256}=\sqrt{1024*94}=\sqrt{1024}*\sqrt{94}=32\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-32\sqrt{94}}{2*64}=\frac{96-32\sqrt{94}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+32\sqrt{94}}{2*64}=\frac{96+32\sqrt{94}}{128}
$