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(8x-20)(x+7)=0
We multiply parentheses ..
(+8x^2+56x-20x-140)=0
We get rid of parentheses
8x^2+56x-20x-140=0
We add all the numbers together, and all the variables
8x^2+36x-140=0
a = 8; b = 36; c = -140;
Δ = b2-4ac
Δ = 362-4·8·(-140)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-76}{2*8}=\frac{-112}{16} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+76}{2*8}=\frac{40}{16} =2+1/2 $
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