(8x-20)=(2x+32)

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Solution for (8x-20)=(2x+32) equation: 



(8x-20)=(2x+32)

We move all terms to the left:

(8x-20)-((2x+32))=0

We get rid of parentheses

8x-((2x+32))-20=0



We calculate terms in parentheses: -((2x+32)), so:

(2x+32)

We get rid of parentheses

2x+32

Back to the equation:

-(2x+32)



We get rid of parentheses

8x-2x-32-20=0

We add all the numbers together, and all the variables

6x-52=0

We move all terms containing x to the left, all other terms to the right

6x=52

x=52/6

x=8+2/3

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