(8x-28)+(3x+4)=108

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Solution for (8x-28)+(3x+4)=108 equation: 



(8x-28)+(3x+4)=108

We move all terms to the left:

(8x-28)+(3x+4)-(108)=0

We get rid of parentheses

8x+3x-28+4-108=0

We add all the numbers together, and all the variables

11x-132=0

We move all terms containing x to the left, all other terms to the right

11x=132

x=132/11

x=12

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