(8x-28)=(4x+4)

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Solution for (8x-28)=(4x+4) equation: 



(8x-28)=(4x+4)

We move all terms to the left:

(8x-28)-((4x+4))=0

We get rid of parentheses

8x-((4x+4))-28=0



We calculate terms in parentheses: -((4x+4)), so:

(4x+4)

We get rid of parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

8x-4x-4-28=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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