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(8x-3)/(4x+1)=0
Domain of the equation: (4x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
4x!=-1
x!=-1/4
x!=-1/4
x∈R
(8x-3)=0
We get rid of parentheses
8x-3=0
We move all terms containing x to the left, all other terms to the right
8x=3
x=3/8
x=3/8
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