(8x-35)=(2x+37)

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Solution for (8x-35)=(2x+37) equation: 



(8x-35)=(2x+37)

We move all terms to the left:

(8x-35)-((2x+37))=0

We get rid of parentheses

8x-((2x+37))-35=0



We calculate terms in parentheses: -((2x+37)), so:

(2x+37)

We get rid of parentheses

2x+37

Back to the equation:

-(2x+37)



We get rid of parentheses

8x-2x-37-35=0

We add all the numbers together, and all the variables

6x-72=0

We move all terms containing x to the left, all other terms to the right

6x=72

x=72/6

x=12

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