(8x-35)=(6x-5)=(3x-1)

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Solution for (8x-35)=(6x-5)=(3x-1) equation: 



(8x-35)=(6x-5)=(3x-1)

We move all terms to the left:

(8x-35)-((6x-5))=0

We get rid of parentheses

8x-((6x-5))-35=0



We calculate terms in parentheses: -((6x-5)), so:

(6x-5)

We get rid of parentheses

6x-5

Back to the equation:

-(6x-5)



We get rid of parentheses

8x-6x+5-35=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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