(8x-37)=(2x+35)

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Solution for (8x-37)=(2x+35) equation:



(8x-37)=(2x+35)
We move all terms to the left:
(8x-37)-((2x+35))=0
We get rid of parentheses
8x-((2x+35))-37=0
We calculate terms in parentheses: -((2x+35)), so:
(2x+35)
We get rid of parentheses
2x+35
Back to the equation:
-(2x+35)
We get rid of parentheses
8x-2x-35-37=0
We add all the numbers together, and all the variables
6x-72=0
We move all terms containing x to the left, all other terms to the right
6x=72
x=72/6
x=12

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