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(8x-3=16x-33)
We move all terms to the left:
(8x-3-(16x-33))=0
We calculate terms in parentheses: +(8x-3-(16x-33)), so:We get rid of parentheses
8x-3-(16x-33)
determiningTheFunctionDomain 8x-(16x-33)-3
We get rid of parentheses
8x-16x+33-3
We add all the numbers together, and all the variables
-8x+30
Back to the equation:
+(-8x+30)
-8x+30=0
We move all terms containing x to the left, all other terms to the right
-8x=-30
x=-30/-8
x=3+3/4
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