(8x-4)(2x+4)=0

Solution for (8x-4)(2x+4)=0 equation:

(8x-4)(2x+4)=0

We multiply parentheses ..

(+16x^2+32x-8x-16)=0

We get rid of parentheses

16x^2+32x-8x-16=0

We add all the numbers together, and all the variables

16x^2+24x-16=0

a = 16; b = 24; c = -16;
Δ = b2-4ac
Δ = 242-4·16·(-16)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-40}{2*16}=\frac{-64}{32}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+40}{2*16}=\frac{16}{32}
=1/2
$