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(8x-4)(3+6x)=0
We add all the numbers together, and all the variables
(8x-4)(6x+3)=0
We multiply parentheses ..
(+48x^2+24x-24x-12)=0
We get rid of parentheses
48x^2+24x-24x-12=0
We add all the numbers together, and all the variables
48x^2-12=0
a = 48; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·48·(-12)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*48}=\frac{-48}{96} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*48}=\frac{48}{96} =1/2 $
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