(8x-4)(6x+4)=(4x+3

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Solution for (8x-4)(6x+4)=(4x+3 equation: 



(8x-4)(6x+4)=(4x+3

We move all terms to the left:

(8x-4)(6x+4)-((4x+3)=0

We multiply parentheses ..

(+48x^2+32x-24x-16)-((4x+3)=0



We calculate terms in parentheses: -((4x+3), so:

(4x+3



We get rid of parentheses

48x^2+32x-24x-((4x+3)-16=0

We add all the numbers together, and all the variables

48x^2+8x-((4x+3)-16=0

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