(8x-4)(6x+4)=(4x+3)(12x-1

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Solution for (8x-4)(6x+4)=(4x+3)(12x-1 equation: 



(8x-4)(6x+4)=(4x+3)(12x-1

We move all terms to the left:

(8x-4)(6x+4)-((4x+3)(12x-1)=0

We multiply parentheses ..

(+48x^2+32x-24x-16)-((4x+3)(12x-1)=0



We calculate terms in parentheses: -((4x+3)(12x-1), so:

(4x+3)(12x-1



We get rid of parentheses

48x^2+32x-24x-((4x+3)(12x-1)-16=0

We multiply parentheses ..

48x^2-((+48x^2-4x+36x-3)-16+32x-24x=0

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