(8x-4)(8x-4)=0

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Solution for (8x-4)(8x-4)=0 equation: 



(8x-4)(8x-4)=0

We multiply parentheses ..

(+64x^2-32x-32x+16)=0

We get rid of parentheses

64x^2-32x-32x+16=0

We add all the numbers together, and all the variables

64x^2-64x+16=0

a = 64; b = -64; c = +16;
Δ = b2-4ac
Δ = -642-4·64·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{64}{128}=1/2$

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