(8x-4)+(3x+9)=10/12

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Solution for (8x-4)+(3x+9)=10/12 equation: 



(8x-4)+(3x+9)=10/12

We move all terms to the left:

(8x-4)+(3x+9)-(10/12)=0

We add all the numbers together, and all the variables

(8x-4)+(3x+9)-(+10/12)=0

We get rid of parentheses

8x+3x-4+9-10/12=0

We multiply all the terms by the denominator


8x*12+3x*12-10-4*12+9*12=0

We add all the numbers together, and all the variables

8x*12+3x*12+50=0

Wy multiply elements

96x+36x+50=0

We add all the numbers together, and all the variables

132x+50=0

We move all terms containing x to the left, all other terms to the right

132x=-50

x=-50/132

x=-25/66

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