(8x-4)+(6x+6)=(3x-2)

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Solution for (8x-4)+(6x+6)=(3x-2) equation:



(8x-4)+(6x+6)=(3x-2)
We move all terms to the left:
(8x-4)+(6x+6)-((3x-2))=0
We get rid of parentheses
8x+6x-((3x-2))-4+6=0
We calculate terms in parentheses: -((3x-2)), so:
(3x-2)
We get rid of parentheses
3x-2
Back to the equation:
-(3x-2)
We add all the numbers together, and all the variables
14x-(3x-2)+2=0
We get rid of parentheses
14x-3x+2+2=0
We add all the numbers together, and all the variables
11x+4=0
We move all terms containing x to the left, all other terms to the right
11x=-4
x=-4/11
x=-4/11

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