(8x-4)/2=(6x-3)/5

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Solution for (8x-4)/2=(6x-3)/5 equation: 



(8x-4)/2=(6x-3)/5

We move all terms to the left:

(8x-4)/2-((6x-3)/5)=0

We calculate fractions


8x/()+(-((6x-3)*2)/()=0



We calculate terms in parentheses: +(-((6x-3)*2)/(), so:

-((6x-3)*2)/(

We multiply all the terms by the denominator


-((6x-3)*2)



We calculate terms in parentheses: -((6x-3)*2), so:

(6x-3)*2

We multiply parentheses

12x-6

Back to the equation:

-(12x-6)



We get rid of parentheses

-12x+6

Back to the equation:

+(-12x+6)



We get rid of parentheses

8x/()-12x+6=0

We multiply all the terms by the denominator


8x-12x*()+6*()=0

We add all the numbers together, and all the variables

8x-12x*()=0

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