(8x-4)=(4x+3)+(3x+8)

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Solution for (8x-4)=(4x+3)+(3x+8) equation: 



(8x-4)=(4x+3)+(3x+8)

We move all terms to the left:

(8x-4)-((4x+3)+(3x+8))=0

We get rid of parentheses

8x-((4x+3)+(3x+8))-4=0



We calculate terms in parentheses: -((4x+3)+(3x+8)), so:

(4x+3)+(3x+8)

We get rid of parentheses

4x+3x+3+8

We add all the numbers together, and all the variables

7x+11

Back to the equation:

-(7x+11)



We get rid of parentheses

8x-7x-11-4=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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