(8x-4)=(4x-1)+(2x+1)

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Solution for (8x-4)=(4x-1)+(2x+1) equation: 



(8x-4)=(4x-1)+(2x+1)

We move all terms to the left:

(8x-4)-((4x-1)+(2x+1))=0

We get rid of parentheses

8x-((4x-1)+(2x+1))-4=0



We calculate terms in parentheses: -((4x-1)+(2x+1)), so:

(4x-1)+(2x+1)

We get rid of parentheses

4x+2x-1+1

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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