(8x-4)=3(x-1)+7

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Solution for (8x-4)=3(x-1)+7 equation: 



(8x-4)=3(x-1)+7

We move all terms to the left:

(8x-4)-(3(x-1)+7)=0

We get rid of parentheses

8x-(3(x-1)+7)-4=0



We calculate terms in parentheses: -(3(x-1)+7), so:

3(x-1)+7

We multiply parentheses

3x-3+7

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

8x-3x-4-4=0

We add all the numbers together, and all the variables

5x-8=0

We move all terms containing x to the left, all other terms to the right

5x=8

x=8/5

x=1+3/5

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