(8x-41)-8x=(4x+35)-8x

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Solution for (8x-41)-8x=(4x+35)-8x equation: 



(8x-41)-8x=(4x+35)-8x

We move all terms to the left:

(8x-41)-8x-((4x+35)-8x)=0

We add all the numbers together, and all the variables

-8x+(8x-41)-((4x+35)-8x)=0

We get rid of parentheses

-8x+8x-((4x+35)-8x)-41=0



We calculate terms in parentheses: -((4x+35)-8x), so:

(4x+35)-8x

We add all the numbers together, and all the variables

-8x+(4x+35)

We get rid of parentheses

-8x+4x+35

We add all the numbers together, and all the variables

-4x+35

Back to the equation:

-(-4x+35)



We add all the numbers together, and all the variables

-(-4x+35)-41=0

We get rid of parentheses

4x-35-41=0

We add all the numbers together, and all the variables

4x-76=0

We move all terms containing x to the left, all other terms to the right

4x=76

x=76/4

x=19

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