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(8x-4=6x-12)
We move all terms to the left:
(8x-4-(6x-12))=0
We calculate terms in parentheses: +(8x-4-(6x-12)), so:We get rid of parentheses
8x-4-(6x-12)
determiningTheFunctionDomain 8x-(6x-12)-4
We get rid of parentheses
8x-6x+12-4
We add all the numbers together, and all the variables
2x+8
Back to the equation:
+(2x+8)
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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