(8x-5)(2x-3)=

Solution for (8x-5)(2x-3)= equation:

(8x-5)(2x-3)=

We move all terms to the left:

(8x-5)(2x-3)-()=0

We add all the numbers together, and all the variables

(8x-5)(2x-3)=0

We multiply parentheses ..

(+16x^2-24x-10x+15)=0

We get rid of parentheses

16x^2-24x-10x+15=0

We add all the numbers together, and all the variables

16x^2-34x+15=0

a = 16; b = -34; c = +15;
Δ = b2-4ac
Δ = -342-4·16·15
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-14}{2*16}=\frac{20}{32}
=5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+14}{2*16}=\frac{48}{32}
=1+1/2
$