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(8x-5)(7x=6)
We move all terms to the left:
(8x-5)(7x-(6))=0
We multiply parentheses ..
(+56x^2-48x-35x+30)=0
We get rid of parentheses
56x^2-48x-35x+30=0
We add all the numbers together, and all the variables
56x^2-83x+30=0
a = 56; b = -83; c = +30;
Δ = b2-4ac
Δ = -832-4·56·30
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-83)-13}{2*56}=\frac{70}{112} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-83)+13}{2*56}=\frac{96}{112} =6/7 $
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