(8x-5)/(7x+1)=4/5

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Solution for (8x-5)/(7x+1)=4/5 equation: 



(8x-5)/(7x+1)=4/5

We move all terms to the left:

(8x-5)/(7x+1)-(4/5)=0



Domain of the equation: (7x+1)!=0

We move all terms containing x to the left, all other terms to the right

7x!=-1

x!=-1/7

x!=-1/7

x∈R



We add all the numbers together, and all the variables

(8x-5)/(7x+1)-(+4/5)=0

We get rid of parentheses

(8x-5)/(7x+1)-4/5=0

We calculate fractions


(40x-25)/(35x+5)+(-28x-4)/(35x+5)=0

We multiply all the terms by the denominator


(40x-25)+(-28x-4)=0

We get rid of parentheses

40x-28x-25-4=0

We add all the numbers together, and all the variables

12x-29=0

We move all terms containing x to the left, all other terms to the right

12x=29

x=29/12

x=2+5/12

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