(8x-6)(7x+4)=0

Solution for (8x-6)(7x+4)=0 equation:

(8x-6)(7x+4)=0

We multiply parentheses ..

(+56x^2+32x-42x-24)=0

We get rid of parentheses

56x^2+32x-42x-24=0

We add all the numbers together, and all the variables

56x^2-10x-24=0

a = 56; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·56·(-24)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-74}{2*56}=\frac{-64}{112}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+74}{2*56}=\frac{84}{112}
=3/4
$