(8x-6)=4(x+3)

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Solution for (8x-6)=4(x+3) equation: 



(8x-6)=4(x+3)

We move all terms to the left:

(8x-6)-(4(x+3))=0

We get rid of parentheses

8x-(4(x+3))-6=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

8x-4x-12-6=0

We add all the numbers together, and all the variables

4x-18=0

We move all terms containing x to the left, all other terms to the right

4x=18

x=18/4

x=4+1/2

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