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(8x-7)(4x+2)=0
We multiply parentheses ..
(+32x^2+16x-28x-14)=0
We get rid of parentheses
32x^2+16x-28x-14=0
We add all the numbers together, and all the variables
32x^2-12x-14=0
a = 32; b = -12; c = -14;
Δ = b2-4ac
Δ = -122-4·32·(-14)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-44}{2*32}=\frac{-32}{64} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+44}{2*32}=\frac{56}{64} =7/8 $
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