(8x-7)(5x+4)=40x(x-18)

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Solution for (8x-7)(5x+4)=40x(x-18) equation: 



(8x-7)(5x+4)=40x(x-18)

We move all terms to the left:

(8x-7)(5x+4)-(40x(x-18))=0

We multiply parentheses ..

(+40x^2+32x-35x-28)-(40x(x-18))=0



We calculate terms in parentheses: -(40x(x-18)), so:

40x(x-18)

We multiply parentheses

40x^2-720x

Back to the equation:

-(40x^2-720x)



We get rid of parentheses

40x^2-40x^2+32x-35x+720x-28=0

We add all the numbers together, and all the variables

717x-28=0

We move all terms containing x to the left, all other terms to the right

717x=28

x=28/717

x=28/717

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