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(8x-7)(6x+6)=0
We multiply parentheses ..
(+48x^2+48x-42x-42)=0
We get rid of parentheses
48x^2+48x-42x-42=0
We add all the numbers together, and all the variables
48x^2+6x-42=0
a = 48; b = 6; c = -42;
Δ = b2-4ac
Δ = 62-4·48·(-42)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-90}{2*48}=\frac{-96}{96} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+90}{2*48}=\frac{84}{96} =7/8 $
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