(8x-7)+29=(10x-6)

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Solution for (8x-7)+29=(10x-6) equation:



(8x-7)+29=(10x-6)
We move all terms to the left:
(8x-7)+29-((10x-6))=0
We get rid of parentheses
8x-((10x-6))-7+29=0
We calculate terms in parentheses: -((10x-6)), so:
(10x-6)
We get rid of parentheses
10x-6
Back to the equation:
-(10x-6)
We add all the numbers together, and all the variables
8x-(10x-6)+22=0
We get rid of parentheses
8x-10x+6+22=0
We add all the numbers together, and all the variables
-2x+28=0
We move all terms containing x to the left, all other terms to the right
-2x=-28
x=-28/-2
x=+14

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