(8x-7)+29=(10x-6)

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Solution for (8x-7)+29=(10x-6) equation: 



(8x-7)+29=(10x-6)

We move all terms to the left:

(8x-7)+29-((10x-6))=0

We get rid of parentheses

8x-((10x-6))-7+29=0



We calculate terms in parentheses: -((10x-6)), so:

(10x-6)

We get rid of parentheses

10x-6

Back to the equation:

-(10x-6)



We add all the numbers together, and all the variables

8x-(10x-6)+22=0

We get rid of parentheses

8x-10x+6+22=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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