(8x-8)(2x-14)=0

Solution for (8x-8)(2x-14)=0 equation:

(8x-8)(2x-14)=0

We multiply parentheses ..

(+16x^2-112x-16x+112)=0

We get rid of parentheses

16x^2-112x-16x+112=0

We add all the numbers together, and all the variables

16x^2-128x+112=0

a = 16; b = -128; c = +112;
Δ = b2-4ac
Δ = -1282-4·16·112
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-96}{2*16}=\frac{32}{32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+96}{2*16}=\frac{224}{32}
=7
$