(8x-8)(3x+4)=0

Solution for (8x-8)(3x+4)=0 equation:

(8x-8)(3x+4)=0

We multiply parentheses ..

(+24x^2+32x-24x-32)=0

We get rid of parentheses

24x^2+32x-24x-32=0

We add all the numbers together, and all the variables

24x^2+8x-32=0

a = 24; b = 8; c = -32;
Δ = b2-4ac
Δ = 82-4·24·(-32)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*24}=\frac{-64}{48}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*24}=\frac{48}{48}
=1
$