(8x-8)(4x+16)=0

Solution for (8x-8)(4x+16)=0 equation:

(8x-8)(4x+16)=0

We multiply parentheses ..

(+32x^2+128x-32x-128)=0

We get rid of parentheses

32x^2+128x-32x-128=0

We add all the numbers together, and all the variables

32x^2+96x-128=0

a = 32; b = 96; c = -128;
Δ = b2-4ac
Δ = 962-4·32·(-128)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-160}{2*32}=\frac{-256}{64}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+160}{2*32}=\frac{64}{64}
=1
$