(8x-8)(7x+3)=0

Solution for (8x-8)(7x+3)=0 equation:

(8x-8)(7x+3)=0

We multiply parentheses ..

(+56x^2+24x-56x-24)=0

We get rid of parentheses

56x^2+24x-56x-24=0

We add all the numbers together, and all the variables

56x^2-32x-24=0

a = 56; b = -32; c = -24;
Δ = b2-4ac
Δ = -322-4·56·(-24)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-80}{2*56}=\frac{-48}{112}
=-3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+80}{2*56}=\frac{112}{112}
=1
$