(8x-9)2=(9x+3)3

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Solution for (8x-9)2=(9x+3)3 equation: 



(8x-9)2=(9x+3)3

We move all terms to the left:

(8x-9)2-((9x+3)3)=0

We multiply parentheses

16x-((9x+3)3)-18=0



We calculate terms in parentheses: -((9x+3)3), so:

(9x+3)3

We multiply parentheses

27x+9

Back to the equation:

-(27x+9)



We get rid of parentheses

16x-27x-9-18=0

We add all the numbers together, and all the variables

-11x-27=0

We move all terms containing x to the left, all other terms to the right

-11x=27

x=27/-11

x=-2+5/11

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