(8y+1)-(4y+3)=

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Solution for (8y+1)-(4y+3)= equation:


Simplifying
(8y + 1) + -1(4y + 3) = 0

Reorder the terms:
(1 + 8y) + -1(4y + 3) = 0

Remove parenthesis around (1 + 8y)
1 + 8y + -1(4y + 3) = 0

Reorder the terms:
1 + 8y + -1(3 + 4y) = 0
1 + 8y + (3 * -1 + 4y * -1) = 0
1 + 8y + (-3 + -4y) = 0

Reorder the terms:
1 + -3 + 8y + -4y = 0

Combine like terms: 1 + -3 = -2
-2 + 8y + -4y = 0

Combine like terms: 8y + -4y = 4y
-2 + 4y = 0

Solving
-2 + 4y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 4y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 4y = 0 + 2
4y = 0 + 2

Combine like terms: 0 + 2 = 2
4y = 2

Divide each side by '4'.
y = 0.5

Simplifying
y = 0.5

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