(8y+2)/6=11

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Solution for (8y+2)/6=11 equation: 



(8y+2)/6=11

We move all terms to the left:

(8y+2)/6-(11)=0

We multiply all the terms by the denominator


(8y+2)-11*6=0

We add all the numbers together, and all the variables

(8y+2)-66=0

We get rid of parentheses

8y+2-66=0

We add all the numbers together, and all the variables

8y-64=0

We move all terms containing y to the left, all other terms to the right

8y=64

y=64/8

y=8

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