(8y+3)+(4y+5)=80

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Solution for (8y+3)+(4y+5)=80 equation: 



(8y+3)+(4y+5)=80

We move all terms to the left:

(8y+3)+(4y+5)-(80)=0

We get rid of parentheses

8y+4y+3+5-80=0

We add all the numbers together, and all the variables

12y-72=0

We move all terms containing y to the left, all other terms to the right

12y=72

y=72/12

y=6

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