(8y+42)=(5y-9)+90

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Solution for (8y+42)=(5y-9)+90 equation: 



(8y+42)=(5y-9)+90

We move all terms to the left:

(8y+42)-((5y-9)+90)=0

We get rid of parentheses

8y-((5y-9)+90)+42=0



We calculate terms in parentheses: -((5y-9)+90), so:

(5y-9)+90

We get rid of parentheses

5y-9+90

We add all the numbers together, and all the variables

5y+81

Back to the equation:

-(5y+81)



We get rid of parentheses

8y-5y-81+42=0

We add all the numbers together, and all the variables

3y-39=0

We move all terms containing y to the left, all other terms to the right

3y=39

y=39/3

y=13

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