(8y+5)=(8y+5)(8y+5)

Solution for (8y+5)=(8y+5)(8y+5) equation:

(8y+5)=(8y+5)(8y+5)

We move all terms to the left:

(8y+5)-((8y+5)(8y+5))=0

We get rid of parentheses

8y-((8y+5)(8y+5))+5=0

We multiply parentheses ..

-((+64y^2+40y+40y+25))+8y+5=0


We calculate terms in parentheses: -((+64y^2+40y+40y+25)), so:

(+64y^2+40y+40y+25)

We get rid of parentheses

64y^2+40y+40y+25

We add all the numbers together, and all the variables

64y^2+80y+25

Back to the equation:

-(64y^2+80y+25)


We add all the numbers together, and all the variables

8y-(64y^2+80y+25)+5=0

We get rid of parentheses

-64y^2+8y-80y-25+5=0

We add all the numbers together, and all the variables

-64y^2-72y-20=0

a = -64; b = -72; c = -20;
Δ = b2-4ac
Δ = -722-4·(-64)·(-20)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8}{2*-64}=\frac{64}{-128}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8}{2*-64}=\frac{80}{-128}
=-5/8
$