(8y+6)/3=41-(8y+3)/5

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Solution for (8y+6)/3=41-(8y+3)/5 equation: 



(8y+6)/3=41-(8y+3)/5

We move all terms to the left:

(8y+6)/3-(41-(8y+3)/5)=0

We calculate fractions


8y/()+(-(41-(8y+3)*3)/()=0



We calculate terms in parentheses: +(-(41-(8y+3)*3)/(), so:

-(41-(8y+3)*3)/(

We multiply all the terms by the denominator


-(41-(8y+3)*3)



We calculate terms in parentheses: -(41-(8y+3)*3), so:

41-(8y+3)*3

determiningTheFunctionDomain
-(8y+3)*3+41

We multiply parentheses

-24y-9+41

We add all the numbers together, and all the variables

-24y+32

Back to the equation:

-(-24y+32)



We get rid of parentheses

24y-32

Back to the equation:

+(24y-32)



We get rid of parentheses

8y/()+24y-32=0

We multiply all the terms by the denominator


8y+24y*()-32*()=0

We add all the numbers together, and all the variables

8y+24y*()=0

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