(8y+6)=(3y-4)

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Solution for (8y+6)=(3y-4) equation: 



(8y+6)=(3y-4)

We move all terms to the left:

(8y+6)-((3y-4))=0

We get rid of parentheses

8y-((3y-4))+6=0



We calculate terms in parentheses: -((3y-4)), so:

(3y-4)

We get rid of parentheses

3y-4

Back to the equation:

-(3y-4)



We get rid of parentheses

8y-3y+4+6=0

We add all the numbers together, and all the variables

5y+10=0

We move all terms containing y to the left, all other terms to the right

5y=-10

y=-10/5

y=-2

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